Swift_R16
New Member
After doing stringent research on how to calculate it. Here is what I have, first you need the diameter and weight of the vehicles flywheel and clutch assembly for manual, or, Flexplate and Torque Converter for Automatics
Standard Formula:
I = (1/2) * m * r^2
I = Inertia in kg*m^2
m = mass in kg
r = radius of disc
Example I used for my 2018 Ford Fusion with 2.5L 6 Speed Auto:
Flexplate (Diameter: 11.38 inches/ Mass: 5 lbs) :
I = (1/2) * 2.26796 kg * (0.144526 m)^2 = 0.024 kg*m^2.
Torque Converter (Diameter: 10.5 inches/ Mass: 30.60 lbs):
I = (1/2) * 13.87993 kg * (0.13335 m)^2 = 0.124 kg*m^2.
0.124 + 0.024 = 0.148
The sum of the two "I" of the two Flywheel/Flexplate, Clutch/Torque should roughly give you a proper number. According to the AC mod guide, a typical value is between 0.100 - 0.150. Currently I'm experimenting with higher numbers as a value of 0.288 (A mess up in my math earlier) somehow seems more accurate to my engine irl based on throttle input.
Standard Formula:
I = (1/2) * m * r^2
I = Inertia in kg*m^2
m = mass in kg
r = radius of disc
Example I used for my 2018 Ford Fusion with 2.5L 6 Speed Auto:
Flexplate (Diameter: 11.38 inches/ Mass: 5 lbs) :
I = (1/2) * 2.26796 kg * (0.144526 m)^2 = 0.024 kg*m^2.
Torque Converter (Diameter: 10.5 inches/ Mass: 30.60 lbs):
I = (1/2) * 13.87993 kg * (0.13335 m)^2 = 0.124 kg*m^2.
0.124 + 0.024 = 0.148
The sum of the two "I" of the two Flywheel/Flexplate, Clutch/Torque should roughly give you a proper number. According to the AC mod guide, a typical value is between 0.100 - 0.150. Currently I'm experimenting with higher numbers as a value of 0.288 (A mess up in my math earlier) somehow seems more accurate to my engine irl based on throttle input.
